10x^2-19x+11=

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Solution for 10x^2-19x+11= equation:


Simplifying
10x2 + -19x + 11 = 0

Reorder the terms:
11 + -19x + 10x2 = 0

Solving
11 + -19x + 10x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
1.1 + -1.9x + x2 = 0

Move the constant term to the right:

Add '-1.1' to each side of the equation.
1.1 + -1.9x + -1.1 + x2 = 0 + -1.1

Reorder the terms:
1.1 + -1.1 + -1.9x + x2 = 0 + -1.1

Combine like terms: 1.1 + -1.1 = 0.0
0.0 + -1.9x + x2 = 0 + -1.1
-1.9x + x2 = 0 + -1.1

Combine like terms: 0 + -1.1 = -1.1
-1.9x + x2 = -1.1

The x term is -1.9x.  Take half its coefficient (-0.95).
Square it (0.9025) and add it to both sides.

Add '0.9025' to each side of the equation.
-1.9x + 0.9025 + x2 = -1.1 + 0.9025

Reorder the terms:
0.9025 + -1.9x + x2 = -1.1 + 0.9025

Combine like terms: -1.1 + 0.9025 = -0.1975
0.9025 + -1.9x + x2 = -0.1975

Factor a perfect square on the left side:
(x + -0.95)(x + -0.95) = -0.1975

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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